What is the current draw in amps for a 2,500 watt load on a 208 volt, 3-phase circuit?

To determine the current draw in amps for a 2,500 watt load on a 208 volt, 3-phase circuit, you can use the formula for calculating current in a 3-phase power system, which is:

[ \text{Current (I)} = \frac{\text{Power (P)}}{\text{Voltage (V)} \times \sqrt{3}} ]

In this case, the power (P) is 2,500 watts, and the voltage (V) is 208 volts. The factor of (\sqrt{3}) (approximately 1.732) is used because the formula is specific to 3-phase systems.

Plugging the values into the formula gives:

[ I = \frac{2500}{208 \times 1.732} ]

Calculating the denominator:

[ 208 \times 1.732 \approx 360.256 ]

Now, divide the total power by the calculated voltage:

[ I = \frac{2500}{360.256} \approx 6.94 \text{ Amps} ]

Thus, the current draw for a 2,500 watt load on a 208 volt, 3-phase circuit is indeed